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7. Product and Process Comparisons
7.3. Comparisons based on data from two processes

7.3.2.

Do two processes have the same standard deviation?

Testing hypotheses related to standard deviations from two processes Given two random samples of measurements,

from two independent processes, there are three types of questions regarding the true standard deviations of the processes that can be addressed with the sample data. They are:

  1. Are the standard deviations from the two processes the same?
  2. Is the standard deviation of one process less than the other?
  3. Is the standard deviation of one process greater than the other?
Typical null hypotheses The corresponding null hypotheses that test the true standard deviation of the first process, , against the true standard deviation of the second process, are:
  1. H0: =
  2. H0: <
  3. H0: >
Basic statistics from the two processes The basic statistics for the test are the sample standard deviations

;

and degrees of freedom and respectively.

Form of the test statistic The test statistic is

Test strategies The strategy for testing the hypotheses under (1), (2) or (3) above is to calculate the F statistic from the formula above, and then perform a test at significance level , where is chosen to be small, typically .01, .05 or .10. The hypothesis associated with each case enumerated above is rejected if:

Explanation of critical values The critical values from the F table depend on the significance level and the degrees of freedom in the standard deviations from the two processes. For hypothesis (1): and
Caution on looking up critical values The F distribution has the property that

which means that only upper critical values are required for two-sided tests. However, note that the degrees of freedom are interchanged in the ratio. For example, for a two-sided test at significance level 0.05, go to the F table labeled "2.5% significance level".

  • For , reverse the order of the degrees of freedom; i.e., look across the top of the table for and down the table for .
  • For , look across the top of the table for and down the table for .

Critical values for cases (2) and (3) are defined similarly except that the critical values for the one-sided tests are based on rather than on .

Two-sided confidence interval The two-sided confidence interval for the ratio of the two unknown variances (squares of the standard deviations) is shown below.

One interpretation of the confidence interval is that if the quantity, "one" is contained within the interval, the standard deviations are equivalent.

Example of unequal number of data points A new procedure to assemble a device is introduced and tested for possible improvement in time of assembly. The question being addressed is whether the standard deviation, , of the new assembly process is better than the standard deviation, , for the old assembly process as in hypothesis (3). Data (in minutes required to assemble a device) for both the old and new processes are listed on an earlier page. Relevant statistics are shown below:


                 Process 1          Process 2

Mean                36.0909               32.2222
Standard deviation   4.9082                2.5874
No. measurements         11                     9
Degrees freedom          10                     8
Computation of the test statistic From this table we generate the test statistic

Decision process For a test at the 5% significance level, go to the F table for 5% signficance level, and look up the critical value for numerator degrees of freedom = 8 and denominator degrees of freedom = 10. The critical value is 3.072. Thus, hypothesis (3) cannot be rejected because the test statistic (F = 3.60) is not less than 1/3.072 and, therefore, we cannot reject the notion that process 2 has better precision (smaller standard deviation) than process 1.

Insensitivity of decision process Notice the frustrating fact that this data set does not reject any of the three hypotheses listed above. This may appear to be an inconsistency in the test results but, in fact, it demonstrates how failure to reject a null hypothesis is not equivalent with acceptance of the null hypothesis. In this case, because of the small sample sizes, the test does not have the power to discriminate between process 1 and process 2 given that the sample standard deviations do not differ greatly.
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